NAME

stpcpy - copy a string returning a pointer to its end

SYNOPSIS

#include <string.h>

char *stpcpy(char *dest, const char *src);

Feature Test Macro Requirements for glibc (see feature_test_macros(7)):

stpcpy():

DESCRIPTION

The stpcpy() function copies the string pointed to by src (including the terminating null byte ('\0')) to the array pointed to by dest. The strings may not overlap, and the destination string dest must be large enough to receive the copy.

RETURN VALUE

stpcpy() returns a pointer to the end of the string dest (that is, the address of the terminating null byte) rather than the beginning.

CONFORMING TO

This function was added to POSIX.1-2008. Before that, it was not part of the C or POSIX.1 standards, nor customary on UNIX systems, but was not a GNU invention either. Perhaps it came from MS-DOS. It is also present on the BSDs.

EXAMPLE

For example, this program uses stpcpy() to concatenate foo and bar to produce foobar, which it then prints.

#define _GNU_SOURCE
#include <string.h>
#include <stdio.h>
int
main(void)
{

    char buffer[20];

    char *to = buffer;

    to = stpcpy(to, "foo");

    to = stpcpy(to, "bar");

    printf("%s\n", buffer);
}

BUGS

This function may overrun the buffer dest.

SEE ALSO

bcopy(3), memccpy(3), memcpy(3), memmove(3), stpncpy(3), strcpy(3), string(3), wcpcpy(3)

COLOPHON

This page is part of release 3.36 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/.