NAME

stpcpy - copy a string returning a pointer to its end

SYNOPSIS

#define _GNU_SOURCE

#include <string.h>

char *stpcpy(char *dest, const char *src);

DESCRIPTION

The stpcpy() function copies the string pointed to by src (including the terminating '\0' character) to the array pointed to by dest. The strings may not overlap, and the destination string dest must be large enough to receive the copy.

RETURN VALUE

stpcpy() returns a pointer to the end of the string dest (that is, the address of the terminating null byte) rather than the beginning.

CONFORMING TO

This function is not part of the C or POSIX.1 standards, and is not customary on Unix systems, but is not a GNU invention either. Perhaps it comes from MS-DOS.

EXAMPLE

For example, this program uses stpcpy() to concatenate foo and bar to produce foobar, which it then prints.

#include <string.h>
int
main (void)
{

    char *to = buffer;

    to = stpcpy(to, "foo");

    to = stpcpy(to, "bar");

    printf("%s\n", buffer);
}

SEE ALSO

bcopy(3), memccpy(3), memcpy(3), memmove(3), strcpy(3), wcpcpy(3), feature_test_macros(7)

COLOPHON

This page is part of release 3.10 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/.