NAME

stpcpy - copy a string returning a pointer to its end

SYNOPSIS

#define _GNU_SOURCE

#include <string.h>

char *stpcpy(char *dest, const char *src);

DESCRIPTION

The stpcpy() function copies the string pointed to by src (including the terminating `\0' character) to the array pointed to by dest. The strings may not overlap, and the destination string dest must be large enough to receive the copy.

RETURN VALUE

stpcpy() returns a pointer to the end of the string dest (that is, the address of the terminating null byte) rather than the beginning.

CONFORMING TO

This function is not part of the C or POSIX.1 standards, and is not customary on Unix systems, but is not a GNU invention either. Perhaps it comes from MS-DOS.

EXAMPLE

For example, this program uses stpcpy() to concatenate foo and bar to produce foobar, which it then prints.

#include <string.h>
int
main (void)
{

    char *to = buffer;

    to = stpcpy(to, "foo");

    to = stpcpy(to, "bar");

    printf("%s\n", buffer);
}

SEE ALSO

bcopy(3), memccpy(3), memcpy(3), memmove(3), strcpy(3), wcpcpy(3), feature_test_macros(7)